<span class="MathJax_Preview" style="color: inherit;"><span class="MJXp-math" id="MJXp-Span-1"><span class="MJXp-mstyle" id="MJXp-Span-2"><span class="MJXp-munder" id="MJXp-Span-3"><span class=""><span class="MJXp-mi MJXp-italic" id="MJXp-Span-4">l</span><span class="MJXp-mi MJXp-italic" id="MJXp-Span-5">i</span><span class="MJXp-mi MJXp-italic" id="MJXp-Span-6">m</span></span><span class=" MJXp-script"><span class="MJXp-mi MJXp-italic" id="MJXp-Span-7" style="margin-left: 0px;">x</span><span class="MJXp-mo" id="MJXp-Span-8">→</span><span class="MJXp-mo" id="MJXp-Span-9">+</span><span class="MJXp-mi" id="MJXp-Span-10">∞</span></span></span><span class="MJXp-mo" id="MJXp-Span-11" style="margin-left: 0em; margin-right: 0em;">(</span><span class="MJXp-msqrt" id="MJXp-Span-12"><span class="MJXp-surd"><span style="font-size: 134%; margin-top: 0.104em;">√</span></span><span class="MJXp-root"><span class="MJXp-rule" style="border-top: 0.08em solid;"></span><span class="MJXp-box"><span class="MJXp-mi MJXp-italic" id="MJXp-Span-13">x</span><span class="MJXp-mo" id="MJXp-Span-14" style="margin-left: 0.267em; margin-right: 0.267em;">+</span><span class="MJXp-mn" id="MJXp-Span-15">1</span></span></span></span><span class="MJXp-mo" id="MJXp-Span-16" style="margin-left: 0.267em; margin-right: 0.267em;">−</span><span class="MJXp-msqrt" id="MJXp-Span-17"><span class="MJXp-surd"><span style="font-size: 134%; margin-top: 0.104em;">√</span></span><span class="MJXp-root"><span class="MJXp-rule" style="border-top: 0.08em solid;"></span><span class="MJXp-box"><span class="MJXp-mi MJXp-italic" id="MJXp-Span-18">x</span><span class="MJXp-mo" id="MJXp-Span-19" style="margin-left: 0.267em; margin-right: 0.267em;">−</span><span class="MJXp-mn" id="MJXp-Span-20">3</span></span></span></span><span class="MJXp-mo" id="MJXp-Span-21" style="margin-left: 0em; margin-right: 0em;">)</span></span></span></span><script type="math/tex" id="MathJax-Element-1">\Large \underset{x\rightarrow +\infty}{lim}(\sqrt{x+1}-\sqrt{x-3})</script> b

limx+(x+1x3) b

4/5

Tác giả: Thầy Tùng

Đăng ngày: 18 Aug 2022

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Câu hỏi:

limx+(x+1x3) bằng

Đáp án án đúng là: A

Lời giải chi tiết:

limx+(x+1x3) =limx+x+1(x3)x+1+x3=limx+4x(1+1x+13x)=0.

Chọn đáp án A.