\r\nz_{1}=\\dfrac{-1+\\sqrt{3} i}{2} \\\\
\r\nz_{2}=\\dfrac{-1-\\sqrt{3} i}{2}
\r\n\\end{array}\\right.$
$\\Large z_{1}=\\dfrac{-1+\\sqrt{3} i}{2} \\Rightarrow z_{1}^{3}=1 \\Rightarrow\\left(z_{1}^{3}\\right)^{673}=1^{673}$ $\\Large \\Rightarrow z_{1}^{2019}=1 \\Rightarrow z_{1}^{2021}=z_{1}^{2}=\\dfrac{-1-\\sqrt{3} i}{2}$
\r\n\r\n$\\Large z_{2}=\\dfrac{-1-\\sqrt{3} i}{2} \\Rightarrow z_{2}^{3}=1 \\Rightarrow\\left(z_{2}^{3}\\right)^{673}=1^{673}$ $\\Large \\Rightarrow z_{2}^{2019}=1 \\Rightarrow z_{2}^{2021}=z_{2}^{2}=\\dfrac{-1+\\sqrt{3} i}{2}$
\r\n\r\n$\\Large w =z_{1}^{2021}+z_{2}^{2021}=\\dfrac{-1-\\sqrt{3} i}{2}+\\dfrac{-1+\\sqrt{3} i}{2}=-1$
\r\n","url":"https://hoc357.edu.vn/cau-hoi/goi-large-z-1-z-2-la-cac-nghiem-phuc-cua-phuong-trinh-large-v7674","dateCreated":"2022-08-18T19:16:10.185Z","author":{"@type":"Person","name":"Trần Thanh Hùng"}},"suggestedAnswer":[]}}MỤC LỤC
Gọi $\Large z_{1}, z_{2}$ là các nghiệm phức của phương trình: $\Large z^{2}+z+1=0$, đặt $\Large w=z_{1}^{2021}+z_{2}^{2021}$. Khi đó
Lời giải chi tiết:
Ta có:
$\Large z^{2}+z+1=0 \Leftrightarrow\left[\begin{array}{l}
z_{1}=\dfrac{-1+\sqrt{3} i}{2} \\
z_{2}=\dfrac{-1-\sqrt{3} i}{2}
\end{array}\right.$
$\Large z_{1}=\dfrac{-1+\sqrt{3} i}{2} \Rightarrow z_{1}^{3}=1 \Rightarrow\left(z_{1}^{3}\right)^{673}=1^{673}$ $\Large \Rightarrow z_{1}^{2019}=1 \Rightarrow z_{1}^{2021}=z_{1}^{2}=\dfrac{-1-\sqrt{3} i}{2}$
$\Large z_{2}=\dfrac{-1-\sqrt{3} i}{2} \Rightarrow z_{2}^{3}=1 \Rightarrow\left(z_{2}^{3}\right)^{673}=1^{673}$ $\Large \Rightarrow z_{2}^{2019}=1 \Rightarrow z_{2}^{2021}=z_{2}^{2}=\dfrac{-1+\sqrt{3} i}{2}$
$\Large w =z_{1}^{2021}+z_{2}^{2021}=\dfrac{-1-\sqrt{3} i}{2}+\dfrac{-1+\sqrt{3} i}{2}=-1$
Xem thêm các bài tiếp theo bên dưới