Xét $\Large \int_1^{e}\dfrac{\ln^{2}x}{x}dx$, nếu đặt $\Large u=\ln x$

Xét $\Large \int_1^{e}\dfrac{\ln^{2}x}{x}dx$, nếu đặt $\Large u=\ln x$ thì $\Large \int_1^{e}\dfrac{\ln^{2}x}{x}dx$ bằng

• A. $\Large \int_0^{1}udu$
• B. $\Large -\int_0^{1}u^{2}du$
• C. $\Large \int_1^{e}u^{2}du$
• D. $\Large \int_0^{1}u^{2}du$

Đặt $\Large u=\ln x$, ta có $\Large du=\dfrac{1}{x}dx$

Khi $\Large x=1$ thì $\Large u=0$, khi $\Large x=e$ thì $\Large u=1$

Vậy $\Large \int_1^{e}\dfrac{\ln^{2}x}{x}dx=\int_0^{1}u^{2}du$