Cho $\large \log_23= a$. Tính $\large \log_{36} 24$ theo a A. $\large

Cho $\large \log_23= a$. Tính $\large \log_{36} 24$ theo a

• A. A. $\large T =\dfrac{3+a}{2+2a}$
• B. B. $\large T =\dfrac{2a+3}{a+3}$
• C. C. $\large T =\dfrac{3a+2}{a+2}$
• D. D. $\large T =\dfrac{a+3}{3a+2}$

Chọn A

Ta có: $\large T = \log_{36}24=\dfrac{\log_224}{\log_236}=\dfrac{\log_2(2^3.3)}{\log_2(2^2.3^2)}=\dfrac{3+ \log_23}{2+2\log_23}=\dfrac{3+a}{2+2a}$