Đạo hàm cấp hai

$f'\left( x \right)=3{{x}^{2}}+2\Rightarrow f''\left( x \right)=6x\Rightarrow f''\left( 1 \right)=6$.

$\begin{gathered} f'\left( x \right) = 10x{\left( {{x^2} + 5} \right)^4} \Rightarrow f''\left( x \right) = 10{\left( {{x^2} + 5} \right)^4} + 80{x^2}{\left( {{x^2} + 5} \right)^3} \hfill \\ \Rightarrow f''\left( 1 \right) = 30240 \hfill \\ \end{gathered}$

$\begin{align} & f'\left( x \right)=10x{{\left( {{x}^{2}}+5 \right)}^{4}}\Rightarrow f''\left( x \right)=10{{\left( {{x}^{2}}+5 \right)}^{3}}\left( 9{{x}^{2}}+5 \right) \\ & \Rightarrow f''\left( 1 \right)=30240 \\ \end{align}$