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Đem nung một khối lượng Cu(NO3)2Cu(NO3)2 s

4.8/5

Tác giả: Thầy Tùng

Đăng ngày: 18 Aug 2022

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Câu hỏi:

Đem nung một khối lượng Cu(NO3)2Cu(NO3)2 sau một thời gian dừng lại, làm nguội, rồi cân thấy khối lượng giảm 0,54 gam. Vậy khối lượng muối Cu(NO3)2Cu(NO3)2 đã bị nhiệt phân là

Đáp án án đúng là: B

Lời giải chi tiết:

Khối lượng giảm là =mNO2+O2=mNO2+O2

Cu(NO3)2CuO+2NO2+1/2O22x4xx

46.4x+32x=0,54x=0,0025

nCu(NO3)2 pư=2x=0,005 (mol)

mCu(NO3)2 pư=0,94 (gam)