Tính $\large \lim \dfrac{2^n+1}{2.2^n+3}$ $\large 2$ $\large 0$ $\larg

Tính $\large \lim \dfrac{2^n+1}{2.2^n+3}$

• A.

  $\large 2$

• B.

  $\large 0$

• C.

  $\large 1$

• D.

  $\large \dfrac{1}{2}$

Chọn D

Ta có: $\large \lim \dfrac{2^n+1}{2.2^n+3}=\lim \dfrac{1+\dfrac{1}{2^n}}{2+\dfrac{3}{2^n}}=\dfrac{1+0}{2+0}=\dfrac{1}{2}$