Nếu $\Large \int_{0}^{m}(2 x-1) d x=2$ thì m có giá trị bằng $\Large \

Nếu $\Large \int_{0}^{m}(2 x-1) d x=2$ thì m có giá trị bằng

• A. $\Large \left[\begin{array}{l} m=1 \\ m=-2 \end{array}\right.$
• B. $\Large \left[\begin{array}{l} m=1 \\ m=2 \end{array}\right.$
• C. $\Large \left[\begin{array}{l} m=-1 \\ m=2 \end{array}\right.$
• D. $\Large \left[\begin{array}{l} m=-1 \\ m=-2 \end{array}\right.$

Chọn C

Ta có: $\Large \int_{0}^{m}(2 x-1) d x=\left.2 \Leftrightarrow\left(x^{2}-x\right)\right|_{0} ^{m}=2 \Leftrightarrow m^{2}-m=2 \Leftrightarrow\left[\begin{array}{l}
m=-1 \\
m=2
\end{array}\right.$