Chọn đẳng thức sai: $\Large (x-1)^3+2(x-1)^2=(x-1)^2(x+1)$ \(\Large

Chọn đẳng thức sai:

• A.

  $\Large (x-1)^3+2(x-1)^2=(x-1)^2(x+1)$

• B.

  $\Large {(x - 1)^3} + 2(x - 1) = (x - 1)\left[ {{{(x - 1)}^2} + 2} \right]$

• C.

  $\Large {(x - 1)^3} + 2{(x - 1)^2} = (x - 1)\left[ {{{(x - 1)}^2} + 2x - 2} \right]$

• D.

  $\Large (x-1)^3+2(x-1)^2=(x-1)(x+3)$

Ta có $\Large (x-1)^3+2(x-1)^2=(x-1)^2(x-1+2)=(x-1)^2(x+1)\ne(x-1)(x+3)$