Biết $\large \int\limits_{0}^{1} f(x)\mathrm{d}x = 3$, khi đó $\large

Biết $\large \int\limits_{0}^{1} f(x)\mathrm{d}x = 3$, khi đó  $\large \int\limits_{0}^{1} [4x - 3f(x)] \mathrm{d}x$ bằng 

• A.

  -5

• B.

  11

• C.

  -9

• D.

  -7

Ta có: $\large \int\limits_{0}^{1} [4x - 3f(x)] \mathrm{d}x = \int\limits_{0}^{1} 4x \mathrm{d}x + 3  \int\limits_{0}^{1} f(x)\mathrm{d}x = 2x^{2} |^{1}_{0} - 3.3 = 2 - 9 = -7$