MỤC LỤC
Tính nhanh:
\(\Large B = \dfrac{5}{2}+\dfrac{5}{6}+\dfrac{5}{18}+\dfrac{5}{54}+\dfrac{5}{162}+\dfrac{5}{486}=...\)
( Viết đáp án đúng dưới dạng x/y)
Lời giải chi tiết:
Ta có :
\(\Large B = \dfrac{5}{2}+\dfrac{5}{6}+\dfrac{5}{18}+\dfrac{5}{54}+\dfrac{5}{162}+\dfrac{5}{486}\)
\(\Large 3\times B =3\times( \dfrac{5}{2}+\dfrac{5}{6}+\dfrac{5}{18}+\dfrac{5}{54}+\dfrac{5}{162}+\dfrac{5}{486})\)
\(\Large 3\times B = \dfrac{15}{2}+\dfrac{5}{2}+\dfrac{5}{6}+\dfrac{5}{18}+\dfrac{5}{54}+\dfrac{5}{162}\)
\(\Large 3\times B-B = (\dfrac{15}{2}+\dfrac{5}{2}+\dfrac{5}{6}+\dfrac{5}{18}+\dfrac{5}{54}+\dfrac{5}{162})-(\dfrac{5}{2}+\dfrac{5}{6}+\dfrac{5}{18}+\dfrac{5}{54}+\dfrac{5}{162}+\dfrac{5}{486})\)
\(\Large 2\times B= \dfrac{15}{2}-\dfrac{5}{486}\)
\(\Large 2\times B= \dfrac{3640}{486}=\dfrac{1820}{243}\)
\(\Large B=\dfrac{1820}{243}:2=\dfrac{910}{243}\)
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