Hòa tan m gam hỗn hợp <span class="MathJax_Preview" style="color: inherit;"><span class="MJXp-math" id="MJXp-Span-1"><span class="MJXp-mstyle" id="MJXp-Span-2"><span class="MJXp-mi MJXp-italic" id="MJXp-Span-3">F</span><span class="MJXp-mi MJXp-italic" id="MJXp-Span-4">e</span><span class="MJXp-mi MJXp-italic" id="MJXp-Span-5">O</span><span class="MJXp-mo" id="MJXp-Span-6" style="margin-left: 0em; margin-right: 0.222em;">,</span><span class="MJXp-mi MJXp-italic" id="MJXp-Span-7">F</span><span class="MJXp-mi MJXp-italic" id="MJXp-Span-8">e</span><span class="MJXp-mo" id="MJXp-Span-9" style="margin-left: 0em; margin-right: 0em;">(</span><span class="MJXp-mi MJXp-italic" id="MJXp-Span-10">O</span><span class="MJXp-mi MJXp-italic" id="MJXp-Span-11">H</span><span class="MJXp-msubsup" id="MJXp-Span-12"><span class="MJXp-mo" id="MJXp-Span-13" style="margin-left: 0em; margin-right: 0.05em;">)</span><span class="MJXp-mrow MJXp-script" id="MJXp-Span-14" style="vertical-align: -0.4em;"><span class="MJXp-mn" id="MJXp-Span-15">2</span></span></span><span class="MJXp-mo" id="MJXp-Span-16" style="margin-left: 0em; margin-right: 0.222em;">,</span><span class="MJXp-mi MJXp-italic" id="MJXp-Span-17">F</span><span class="MJXp-mi MJXp-italic" id="MJXp-Span-18">e</span><span class="MJXp-mi MJXp-italic" id="MJXp-Span-19">C</span><span class="MJXp-msubsup" id="MJXp-Span-20"><span class="MJXp-mi MJXp-italic" id="MJXp-Span-21" style="margin-right: 0.05em;">O</span><span class="MJXp-mrow MJXp-script" id="MJXp-Span-22" style="vertical-align: -0.4em;"><span class="MJXp-mn" id="MJXp-Span-23">3</span></span></span></span></span></span><span id="MathJax-Element-1-Frame" class="mjx-chtml MathJax_CHTML MJXc-processed" tabindex="0" style="font-size: 127%;"><span id="MJXc-Node-1" class="mjx-math"><span id="MJXc-Node-2" class="mjx-mrow"><span id="MJXc-Node-3" class="mjx-mstyle"><span id="MJXc-Node-4" class="mjx-mrow" style="font-size: 144%;"><span id="MJXc-Node-5" class="mjx-mi"><span class="mjx-char MJXc-TeX-math-I" style="padding-top: 0.445em; padding-bottom: 0.298em; padding-right: 0.106em;">F</span></span><span id="MJXc-Node-6" class="mjx-mi"><span class="mjx-char MJXc-TeX-math-I" style="padding-top: 0.199em; padding-bottom: 0.298em;">e</span></span><span id="MJXc-Node-7" class="mjx-mi"><span class="mjx-char MJXc-TeX-math-I" style="padding-top: 0.495em; padding-bottom: 0.298em;">O</span></span><span id="MJXc-Node-8" class="mjx-mo"><span class="mjx-char MJXc-TeX-main-R" style="margin-top: -0.145em; padding-bottom: 0.544em;">,</span></span><span id="MJXc-Node-9" class="mjx-mi MJXc-space1"><span class="mjx-char MJXc-TeX-math-I" style="padding-top: 0.445em; padding-bottom: 0.298em; padding-right: 0.106em;">F</span></span><span id="MJXc-Node-10" class="mjx-mi"><span class="mjx-char MJXc-TeX-math-I" style="padding-top: 0.199em; padding-bottom: 0.298em;">e</span></span><span id="MJXc-Node-11" class="mjx-mo"><span class="mjx-char MJXc-TeX-main-R" style="padding-top: 0.445em; padding-bottom: 0.593em;">(</span></span><span id="MJXc-Node-12" class="mjx-mi"><span class="mjx-char MJXc-TeX-math-I" style="padding-top: 0.495em; padding-bottom: 0.298em;">O</span></span><span id="MJXc-Node-13" class="mjx-mi"><span class="mjx-char MJXc-TeX-math-I" style="padding-top: 0.445em; padding-bottom: 0.298em; padding-right: 0.057em;">H</span></span><span id="MJXc-Node-14" class="mjx-msubsup"><span class="mjx-base"><span id="MJXc-Node-15" class="mjx-mo"><span class="mjx-char MJXc-TeX-main-R" style="padding-top: 0.445em; padding-bottom: 0.593em;">)</span></span></span><span class="mjx-sub" style="font-size: 70.7%; vertical-align: -0.212em; padding-right: 0.071em;"><span id="MJXc-Node-16" class="mjx-texatom" style=""><span id="MJXc-Node-17" class="mjx-mrow"><span id="MJXc-Node-18" class="mjx-mn"><span class="mjx-char MJXc-TeX-main-R" style="padding-top: 0.396em; padding-bottom: 0.347em;">2</span></span></span></span></span></span><span id="MJXc-Node-19" class="mjx-mo"><span class="mjx-char MJXc-TeX-main-R" style="margin-top: -0.145em; padding-bottom: 0.544em;">,</span></span><span id="MJXc-Node-20" class="mjx-mi MJXc-space1"><span class="mjx-char MJXc-TeX-math-I" style="padding-top: 0.445em; padding-bottom: 0.298em; padding-right: 0.106em;">F</span></span><span id="MJXc-Node-21" class="mjx-mi"><span class="mjx-char MJXc-TeX-math-I" style="padding-top: 0.199em; padding-bottom: 0.298em;">e</span></span><span id="MJXc-Node-22" class="mjx-mi"><span class="mjx-char MJXc-TeX-math-I" style="padding-top: 0.495em; padding-bottom: 0.298em; padding-right: 0.045em;">C</span></span><span id="MJXc-Node-23" class="mjx-msubsup"><span class="mjx-base"><span id="MJXc-Node-24" class="mjx-mi"><span class="mjx-char MJXc-TeX-math-I" style="padding-top: 0.495em; padding-bottom: 0.298em;">O</span></span></span><span class="mjx-sub" style="font-size: 70.7%; vertical-align: -0.212em; padding-right: 0.071em;"><span id="MJXc-Node-25" class="mjx-texatom" style=""><span id="MJXc-Node-26" class="mjx-mrow"><span id="MJXc-Node-27" class="mjx-mn"><span class="mjx-char MJXc-TeX-main-R" style="padding-top: 0.396em; padding-bottom: 0.347em;">3</span></span></span></span></span></span></span></span></span></span></span><script type="math/tex" id="MathJax-Element-1">\Large FeO, Fe ( OH )_{2}, FeCO _{3}</script> và $\Larg

Hòa tan m gam hỗn hợp FeO,Fe(OH)2,FeCO3FeO,Fe(OH)2,FeCO3 và $\Larg

4.6/5

Tác giả: Thầy Tùng

Đăng ngày: 18 Aug 2022

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Câu hỏi:

Hòa tan m gam hỗn hợp FeO,Fe(OH)2,FeCO3FeO,Fe(OH)2,FeCO3 và Fe3O4Fe3O4 (trong đó Fe3O4Fe3O4 chiếm 1/3 tổng số mol hỗn hợp) vào dung dịch HNO3HNO3 loãng (dư), thu được 8,96 lít (đktc) hỗn hợp khí gồm CO2CO2NONO (sản phẩm khử duy nhất của N+5N+5) có tỉ khối so với H2H2 là 18,5. Số mol HNO3HNO3 phản ứng là: 

Đáp án án đúng là: C

Lời giải chi tiết:

Chọn C

- Quá trình: FeO,Fe(OH)2,FeCO3,Fe3O4m(g)+HNO3

Fe(NO3)3+0,2molCO2+0,2molNO+H2O

BT:enFeO+nFeCO3+nFe(OH)2+nFe3O4=3nNO=0,6mol

- Hướng tư duy 1:

+ Ta có: 

nFe3O4nhh=13 {nFe3O4=0,2molnFeO+nFeCO3(FeO.CO2)+nFe(OH)2(FeO.H2O)=0,4mol

nO=nFeO+nFeO.CO2+nFeO.H2O+4nFe3O4

nHNO3=2nO+4nNO=3,2mol

- Hướng tư duy 2:

BT:FenFe(NO3)3=3nFe3O40,2+nFeO+FeCO3+Fe(OH)20,4=1

BT:NnHNO3=3nFe(NO3)3+nNO=3,2mol