> = < Ta có: \(\Large\dfrac{3}{2} = \dfrac{3\times3}{2\times3} = \dfra

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Ta có:

\(\Large\dfrac{3}{2} = \dfrac{3\times3}{2\times3} = \dfrac{9}{6}\)

\(\Large\dfrac{4}{3} = \dfrac{4\times2}{3\times2} = \dfrac{8}{6}\)

Vì \(\Large\dfrac{9}{6} > \dfrac{8}{6}\) nên \(\Large\dfrac{3}{2} > \dfrac{4}{3}\)