\(\Large \dfrac{2}{3}; \dfrac{5}{6}; \dfrac{4}{2}\) \(\Large \dfrac{4}

• A.

  \(\Large \dfrac{2}{3}; \dfrac{5}{6}; \dfrac{4}{2}\)

• B.

  \(\Large \dfrac{4}{2}; \dfrac{5}{6}; \dfrac{2}{3}\)

• C.

  \(\Large \dfrac{5}{6}; \dfrac{2}{3}; \dfrac{4}{2}\)

• D.

  \(\Large \dfrac{2}{3}; \dfrac{4}{2}; \dfrac{5}{6}\)

\(\Large \dfrac{2}{3} = \dfrac{2 \times 2}{3 \times 2} = \dfrac{4}{6}\)

\(\Large \dfrac{4}{2} = \dfrac{4 \times 3}{2 \times 3} = \dfrac{12}{6}\)

Ta có: \(\Large \dfrac{12}{6} > \dfrac{5}{6} > \dfrac{4}{6}\)

Vậy \(\Large \dfrac{4}{2} > \dfrac{5}{6} > \dfrac{2}{3}\).