MỤC LỤC
Cho sơ đồ sau:
Etilen $ \large \xrightarrow{+H_2O,\,\,xt}\,\,$X$ \large \xrightarrow{xt,\,\,t^0}\,\,$Y $ \large \xrightarrow{xt\,\,Na,\,\,t^0}$ polime M.
Vậy M là:
Lời giải chi tiết:
Etilen ($ \large CH_2=CH_2) \xrightarrow{+H_2O,xt}CH_3CH_2OH\,\,(X) \xrightarrow{xt,t^0}CH_2=CH-CH=CH_2\,\,(Y)$
$\large\xrightarrow{xt\,\,Na,t^0}(-CH_2-CH=CH-CH_2-)_n$ (polime M)
$ \large CH_2=CH_2+H_2O \xrightarrow{H^+,\,\,t^0} CH_3CH_2OH$
$ \large 2CH_3CH_2OH \xrightarrow{Al_2O_3,\,\,Cr_2O_3,\,\,450^0C}CH_2=CH-CH=CH_2+2H_2O+H_2$
$ \large nCH_2=CH-CH=CH_2 \xrightarrow[Na]{xt,\,\,t^0,\,\,p} (-CH_2-CH=CH-CH_2-)_n$ (polibutađien)
Xem thêm các bài tiếp theo bên dưới